To find the number of feet the diver is above the ocean in 2 seconds, we can substitute t=2 into the given formula.
Thus, the number of feet the diver is above the ocean in 2 seconds is given by:
75 - 16(2)^2
Simplifying, we have:
75 - 16(4)
75 - 64
= 11
Therefore, the diver is 11 feet above the ocean in 2 seconds.
A competitive jumps from a height of 75 ft find the number of feet the diver is above the ocean in 2 seconds evaluate for t=2 by using the formula 75 - 16t2 where he t is time in seconds
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