Asked by Andy
The path of a cliff diver as he dives into a lake is given by the equation
y= -(x-10)^2+75, where y meters is the divers height above the water and x meters is the horizontal distance travelled by the diver. What is the maximum hight the diver is above water?
How can I find this answer?
y= -(x-10)^2+75, where y meters is the divers height above the water and x meters is the horizontal distance travelled by the diver. What is the maximum hight the diver is above water?
How can I find this answer?
Answers
Answered by
Henry
y = -(x - 10)^2 + 75.
y = a(x - h)^2 + k.
The above Eqs represent a parabola in
Vertex Form.
Since "a" is neg., the parabola opens downward and the vertex is the maximum
point on the curve.
The coordinates of the vertex are:
V(h , k) = V(10 , 75).
Max ht = k = 75 meters.
y = a(x - h)^2 + k.
The above Eqs represent a parabola in
Vertex Form.
Since "a" is neg., the parabola opens downward and the vertex is the maximum
point on the curve.
The coordinates of the vertex are:
V(h , k) = V(10 , 75).
Max ht = k = 75 meters.
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