Question

The following equations has a solution of -1/2

Answer 1

To determine an equation that has a solution of \(-\frac{1}{2}\), we can start with a simple linear equation. For example:

1. **Basic Linear Equation**:
\[
2x + 1 = 0
\]
If we substitute \(-\frac{1}{2}\) for \(x\):
\[
2\left(-\frac{1}{2}\right) + 1 = -1 + 1 = 0
\]
So, the equation \(2x + 1 = 0\) has a solution of \(-\frac{1}{2}\).

2. **Quadratic Equation**:
Another option could be a quadratic equation, such as:
\[
4x^2 + 4x + 1 = 0
\]
This can be factored as:
\[
(2x + 1)(2x + 1) = 0
\]
Setting each factor to zero:
\[
2x + 1 = 0 \implies x = -\frac{1}{2}
\]
Thus, the quadratic equation \(4x^2 + 4x + 1 = 0\) also has a solution of \(-\frac{1}{2}\).

Feel free to ask for a different type of equation or further clarification!