Asked by Dino cat
Look at these two equations.
Is there an ordered pair that is a solution to BOTH of these linear equations?
"You can type them into the Desmos calculator to see the graph.
y=x+1
y=-x+5
Yes
No
Is there an ordered pair that is a solution to BOTH of these linear equations?
"You can type them into the Desmos calculator to see the graph.
y=x+1
y=-x+5
Yes
No
Answers
Answered by
GPT-4o mini
To determine if there is an ordered pair that is a solution to both equations, we need to find a point where the two lines intersect.
The equations are:
1. \( y = x + 1 \)
2. \( y = -x + 5 \)
We can set them equal to each other to find the intersection:
\[
x + 1 = -x + 5
\]
Now, combine like terms:
\[
x + x = 5 - 1
\]
\[
2x = 4
\]
\[
x = 2
\]
Now, substitute \( x = 2 \) back into one of the original equations to find \( y \):
Using \( y = x + 1 \):
\[
y = 2 + 1 = 3
\]
So, the ordered pair is \( (2, 3) \).
To confirm, we can check this ordered pair in the second equation:
Using \( y = -x + 5 \):
\[
y = -2 + 5 = 3
\]
Since \( (2, 3) \) satisfies both equations, the answer is:
**Yes**, there is an ordered pair \((2, 3)\) that is a solution to both equations.
The equations are:
1. \( y = x + 1 \)
2. \( y = -x + 5 \)
We can set them equal to each other to find the intersection:
\[
x + 1 = -x + 5
\]
Now, combine like terms:
\[
x + x = 5 - 1
\]
\[
2x = 4
\]
\[
x = 2
\]
Now, substitute \( x = 2 \) back into one of the original equations to find \( y \):
Using \( y = x + 1 \):
\[
y = 2 + 1 = 3
\]
So, the ordered pair is \( (2, 3) \).
To confirm, we can check this ordered pair in the second equation:
Using \( y = -x + 5 \):
\[
y = -2 + 5 = 3
\]
Since \( (2, 3) \) satisfies both equations, the answer is:
**Yes**, there is an ordered pair \((2, 3)\) that is a solution to both equations.
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