Question

Use slope-intercept form to write the equation of a line that has a slope of −3 and passes through the point (1, −5).

Use the drop-down menus to select the proper value for each variable that is substituted into the slope-intercept equation.


y =

x =

m =

Answer 1

To write the equation of a line in slope-intercept form (y = mx + b), you need the slope (m) and the y-intercept (b). You've provided the slope as -3 and a point (1, -5) through which the line passes.

1. Start with the slope-intercept form:
\[
y = mx + b
\]

2. Substitute the value of the slope (m = -3) into the equation:
\[
y = -3x + b
\]

3. Now, use the point (1, -5) to find the value of b. Substitute x = 1 and y = -5 into the equation:
\[
-5 = -3(1) + b
\]

4. Solve for b:
\[
-5 = -3 + b
\]
\[
b = -5 + 3
\]
\[
b = -2
\]

5. Now substitute b back into the equation:
\[
y = -3x - 2
\]

So, using the drop-down menus, the values are:

- For \( y \) = \(-3x - 2\)
- For \( x \) = 1
- For \( m \) = -3

The final equation of the line is:

\[
y = -3x - 2
\]