Identify the vertex of y=−10(x+15)2−18.(1 point)

Question

Responses

(−150,−18)
left parenthesis negative 150 comma negative 18 right parenthesis

(15,−18)
left parenthesis 15 comma negative 18 right parenthesis

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

Answer 1

To find the vertex of the quadratic function in vertex form \( y = a(x - h)^2 + k \), we first rewrite the equation given in the format to identify \( h \) and \( k \).

The function you provided is:

\[ y = -10(x + 15)^2 - 18 \]

From this, we can see that:

• \( h = -15 \) (note the sign change since it's \( x + 15 \))
• \( k = -18 \)

Therefore, the vertex is at the point \( (-15, -18) \).

So the correct response is:

\((-15, -18)\)