Question

identify the vertex of y=4(x-25)^2-61

Answer 1

The vertex of the quadratic function y = 4(x - 25)^2 - 61 is the point (25, -61).

Answer 2

determine the zero(s) of the quadratic function y=-5x^2+16x

Answer 3

To find the zeros of the quadratic function y = -5x^2 + 16x, we need to solve the equation -5x^2 + 16x = 0.

First, let's factor out common terms: x(-5x + 16) = 0.

Now, we can set each factor equal to zero:
x = 0
-5x + 16 = 0

Solving the second equation:
-5x = -16
x = 16/5

So, the zeros of the quadratic function are x = 0 and x = 16/5.