Asked by LEE
Identify the vertex and the axis of symmetry of the graph functio
y=3(x+2)^2-3
Could someone please help me
y=3(x+2)^2-3
Could someone please help me
Answers
Answered by
Steve
as you should know, the parabola
y = a(x-h)^2 + k
has vertex at (h,k) and axis x=h.
So, just read them off from your equation. Just be sure to make it fir the format exactly. Your equation is
y = 2(x-(-2)) + (-3), so h = -2 and k = -3
vertex: (-2,-3)
axis: x = -2
y = a(x-h)^2 + k
has vertex at (h,k) and axis x=h.
So, just read them off from your equation. Just be sure to make it fir the format exactly. Your equation is
y = 2(x-(-2)) + (-3), so h = -2 and k = -3
vertex: (-2,-3)
axis: x = -2
Answered by
LEE
Oh thank you for explaining
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