Question

What are the zeros of the graph of & #y=2^2+[5x - 12
•
-6 and 2
-3/5 and 4
3/2and- 4
• 3and - 4

Answer 1

To find the zeros of the graph of the function given in your message, it appears there was a formatting issue. It seems that the function is intended to be \( y = 2^2 + [5x - 12] - 6 \).

Let's simplify the expression first:

1. **Rewrite \( y \)**:
\[
y = 4 + (5x - 12) - 6
\]
Simplifying this gives:
\[
y = 5x - 12 + 4 - 6
\]
\[
y = 5x - 14
\]

2. **Finding the zeros**:
To find the zeros, set \( y = 0 \):
\[
0 = 5x - 14
\]
Solving for \( x \):
\[
5x = 14
\]
\[
x = \frac{14}{5} \quad \text{or} \quad 2.8
\]

Therefore, the zero of the function \( y = 5x - 14 \) is at \( x = \frac{14}{5} \) (or 2.8).

Regarding the other values you mentioned (like \( -6, 2, \frac{-3}{5}, 4, \frac{3}{2}, -4, 3, -4 \)), they don't appear relevant to the calculation of zeros unless the context was around specific values of \( x \) to evaluate.

Please clarify if this addresses your question or if you have additional context to provide!