Question
John invested $2500, part at 8% and the rest at 12% per annum. The two parts earned equal amount of interest in one year. How much was invested at each rate?
Answers
Tiffany
All you have to do is multiply parts of the 2500 by .08 and .12 then find which amount is the same.
EXP 1250 * .08 = 100 1250 * .12 = 150 since those don't match go to 1300*.08 and 1200*.12 and so on untill you find the same answer
EXP 1250 * .08 = 100 1250 * .12 = 150 since those don't match go to 1300*.08 and 1200*.12 and so on untill you find the same answer
Reiny
Let the amount invested at 8% be x
then the amount invested at 12% is 2500-x
.08x = .12(2500-x)
times a 100
8x = 12(2500-x)
8x = 30000 - 12x
20x = 30000
x = 1500
So John investe $1500 at 8% and $1000 at 12%
Check: .08(1500) = 120 , and .12(1000) = 120
then the amount invested at 12% is 2500-x
.08x = .12(2500-x)
times a 100
8x = 12(2500-x)
8x = 30000 - 12x
20x = 30000
x = 1500
So John investe $1500 at 8% and $1000 at 12%
Check: .08(1500) = 120 , and .12(1000) = 120
Tiffany
would you really have to multiply .08 and .12 by 100 or could you leave it the way it is?
Reiny
You could just work with the decimals.
I just like to work with whole numbers rather than decimals or fractions.
That is because calculators did not exist for most of my teaching career and we had to do calculations in our heads or with pencil and paper.
I just like to work with whole numbers rather than decimals or fractions.
That is because calculators did not exist for most of my teaching career and we had to do calculations in our heads or with pencil and paper.
Tiffany
I see well think you for showing me an easier and faster way to figure that problem out. I was taught the long way on most math problems.