Complete the square to identify the vertex of y=x2−16x+14 .(1 point)

To complete the square for the quadratic equation \( y = x^2 - 16x + 14 \), follow these steps:

1. **Identify the coefficient of \( x \)**: The coefficient of \( x \) is -16.

2. **Take half of the coefficient and square it**:
\[
\left(-\frac{16}{2}\right)^2 = (-8)^2 = 64
\]

3. **Rewrite the equation**: Add and subtract this square inside the equation:
\[
y = (x^2 - 16x + 64) - 64 + 14
\]
\[
y = (x - 8)^2 - 50
\]

4. **Determine the vertex**: The vertex form of a parabola is \( y = a(x-h)^2 + k \), where \( (h, k) \) is the vertex. From our equation, we find:
- \( h = 8 \)
- \( k = -50 \)

Thus, the vertex is \( (8, -50) \).

The correct response is:
**(8, -50)**.