Question

1. A 5 kg box is sitting at rest on a perfectly frictionless surface. Suddenly, a 100 N forces pulls it
eastward. Find the acceleration of the box.

Answer 1

To find the acceleration of the box, we can use Newton's second law of motion, which states:

\[
F = ma
\]

where:
- \( F \) is the net force acting on the object,
- \( m \) is the mass of the object,
- \( a \) is the acceleration of the object.

In this case:
- The force (\( F \)) applied to the box is 100 N (eastward).
- The mass (\( m \)) of the box is 5 kg.

We can rearrange the equation to solve for acceleration (\( a \)):

\[
a = \frac{F}{m}
\]

Substituting the known values:

\[
a = \frac{100 \, \text{N}}{5 \, \text{kg}} = 20 \, \text{m/s}^2
\]

Therefore, the acceleration of the box is \( 20 \, \text{m/s}^2 \) eastward.