Asked by Andrey
A mass m is at rest on a horizontal frictionless surface at t=0. Then a constant force F 0 acts on it for a time t 0. Suddenly the force doubles to 2F 0 and remains constant until t=2t 0. Determine the total distance traveled from t=0 to t=2t 0
Answers
Answered by
R_scott
distance during F0 ... d = 1/2 a t^2 = 1/2 (F0 / m) t0^2
distance during 2F0 ... d = 1/2 a t^2 + v t = ...
... 1/2 (2F0 / m)(2t0 - t0)^2 + [(F0 / m) t0] (2t0 - t0)
distance during 2F0 ... d = 1/2 a t^2 + v t = ...
... 1/2 (2F0 / m)(2t0 - t0)^2 + [(F0 / m) t0] (2t0 - t0)
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