Question
A block of mass of 24.0 kg is sitting on a frictionless surface. If the block is initially at rest, and a force of 3.0 N parallel to the surface is applied for 5.0 seconds, what is the final speed of the block?.
Answers
drwls
The acceleration is given by
a = F/m = 1/8 m/s^2
The distance it moves in t = 5.0 s is
X = (1/2)*a*t^2
= (1/16)*25 = 1.563 m
a = F/m = 1/8 m/s^2
The distance it moves in t = 5.0 s is
X = (1/2)*a*t^2
= (1/16)*25 = 1.563 m