To complete the function table for \( h(x) = 2x + 3 \), we will calculate \( h(x) \) for each given value of \( x \).
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For \( x = -4 \): \[ h(-4) = 2(-4) + 3 = -8 + 3 = -5 \]
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For \( x = -1 \): \[ h(-1) = 2(-1) + 3 = -2 + 3 = 1 \]
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For \( x = 0 \): \[ h(0) = 2(0) + 3 = 0 + 3 = 3 \]
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For \( x = 4 \): \[ h(4) = 2(4) + 3 = 8 + 3 = 11 \]
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For \( x = 5 \): \[ h(5) = 2(5) + 3 = 10 + 3 = 13 \]
Now, we can complete the function table:
\[ \begin{array}{|c|c|} \hline x & h(x) \ \hline -4 & -5 \ -1 & 1 \ 0 & 3 \ 4 & 11 \ 5 & 13 \ \hline \end{array} \]