Asked by qwenie
Let f be the function defined by f(x) = 2{x^3} - 4x + 1. Which of the following is an equation of the line tangent to the graph of f at the point x = - 1?
Answers
Answered by
Reiny
I don't see any choices.
y = 2x^3 - 4x + 1
dy/dx = 6x^2 - 4
at x = -1, dy/dx = 6-4 = 2
y = -2 + 4+1 = 3
so we have slope = 2, point is (-1,3)
equation of tangent:
y - 3 = 2(x + 1)
dress it up to whatever form you need.
y = 2x^3 - 4x + 1
dy/dx = 6x^2 - 4
at x = -1, dy/dx = 6-4 = 2
y = -2 + 4+1 = 3
so we have slope = 2, point is (-1,3)
equation of tangent:
y - 3 = 2(x + 1)
dress it up to whatever form you need.
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