Asked by Anonymous

Let f be the function defined by
f(x) =

x^2 if x<0

square root x if 0 ≤ x <1

2-x if 1 ≤ x< 2

x-3 if x ≥ 2

For what numbers x is f not continuos?

1 only
2 only
0 and 2 only
1 and 2 only

Answers

Answered by Damon
0 is ok f(0) = 0
1 is ok, f(1) = 1
2 is NOT ok, f(2) = 0 and -1
Answered by Anonymous
If 0 and 1 is okay which answer would I Pick? It wouldnt be C or D
Answered by Anonymous
Nevermind it says not Continuous. So do I just plug in these numbers to each equation? Like Im confused how to solve it
Answered by Damon
If you get more than one value of f(x) for any x, the value changes instantly there. That is discontinuous. so if x = 2, tragedy.
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