how many kilojoules of heat are absorbed when 1.00L of water is heated from 18 degrees celsius to 85 degrees celsius?

Answer 1

The mass of 1 liter of water is very close to 1 kg
q = (specific heat)*(mass)*deltaT
specific heat of water = 4.18kJ/kg.C
q = (4.18kJ/kg.C)(1.00kg)(85ºC-18ºC)