Asked by brit
how many kilojoules of heat are absorbed when 1.00L of water is heated from 18 degrees celsius to 85 degrees celsius?
Answers
Answered by
GK
The mass of 1 liter of water is very close to 1 kg
q = (specific heat)*(mass)*deltaT
specific heat of water = 4.18kJ/kg.C
q = (4.18kJ/kg.C)(1.00kg)(85ºC-18ºC)
q = (specific heat)*(mass)*deltaT
specific heat of water = 4.18kJ/kg.C
q = (4.18kJ/kg.C)(1.00kg)(85ºC-18ºC)
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