Identify the vertex of y = -10(x + 15) ^2 - 18

Answer 1

To identify the vertex of the quadratic function given in vertex form, we can use the general format of the vertex form of a parabola, which is:

$$y=a(x-h{)}^2+k$$

where $(h,k)$ is the vertex of the parabola.

In your equation:

$$y=-10(x+15{)}^2-18$$

we can rewrite it slightly to match the vertex form:

$$y=-10(x-(-15){)}^2-18$$

From this, we can see that:

• $h=-15$
• $k=-18$

Therefore, the vertex of the parabola is:

$$(-15,-18)$$

So the vertex is $(-15,-18)$.