I need to write this parabola question 2(x+3)^2 -1 in general form. Not sure how to do it. Do I sqaure whats in brackets first? x^2 + 6x +9 then *by 2 so 2x +12x +18 - 1 = 0 Would this be the answer or am I doing it wrong? Any help appreciated.

Answer 1

yes, you are on the right track

y = 2(x+3)^2 -1
= 2(x^2 + 6x + 9) - 1
= 2x^2 + 12x + 18 - 1
= 2x^2 + 12x + 17

Answer 2

whats the
area of a sqaure in sqaure metre?

help me !!