Asked by Jjkkkkn
Write the parabola in standard form x2-6x-5y-1=0
Answers
Answered by
oobleck
x^2 - 6x - 5y - 1 = 0
5y = x^2-6x-1
y = 1/5 x^2 - 6/5 x - 1/5
5y = x^2-6x-1
y = 1/5 x^2 - 6/5 x - 1/5
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