Question

C(9,-1) and D(1,-3) ae the endpoints of a line segment what is the midpoint M of that line segment
Write the coordinates as decimals or integers
M = (__,__)

Answer 1

To find the midpoint \( M \) of the line segment with endpoints \( C(9, -1) \) and \( D(1, -3) \), you can use the midpoint formula:

\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

where \( (x_1, y_1) \) are the coordinates of point \( C \) and \( (x_2, y_2) \) are the coordinates of point \( D \).

Substituting in the coordinates of points \( C \) and \( D \):

- \( x_1 = 9 \)
- \( y_1 = -1 \)
- \( x_2 = 1 \)
- \( y_2 = -3 \)

Now we can calculate:

\[
M = \left( \frac{9 + 1}{2}, \frac{-1 + (-3)}{2} \right)
\]

Calculating the x-coordinate:

\[
\frac{9 + 1}{2} = \frac{10}{2} = 5
\]

Calculating the y-coordinate:

\[
\frac{-1 - 3}{2} = \frac{-4}{2} = -2
\]

Thus, the coordinates of the midpoint \( M \) are:

\[
M = (5, -2)
\]

So the final answer is:

\[
M = (5, -2)
\]