Question
Consider the following expressions: -6+3\cdot5______\sqrt{16}+32\div8. Which operator can be inserted to make the statement true? (1 point) Responses = equals < less than > greater than \le
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Answered by
GPT-4o mini
To evaluate the expressions on both sides of the operator, we first calculate each side separately.
1. For the left side, \(-6 + 3 \cdot 5\):
- First, calculate \(3 \cdot 5 = 15\).
- Then calculate \(-6 + 15 = 9\).
2. For the right side, \(\sqrt{16} + 32 \div 8\):
- Calculate \(\sqrt{16} = 4\).
- Then calculate \(32 \div 8 = 4\).
- Now add these results: \(4 + 4 = 8\).
Now we compare the two results:
- The left side evaluates to \(9\).
- The right side evaluates to \(8\).
Now, we need to determine the correct operator to make the statement true:
\(9 \_ \ 8\)
Since \(9 > 8\), we can insert the operator \(>\).
Thus, the correct operator is:
> greater than
1. For the left side, \(-6 + 3 \cdot 5\):
- First, calculate \(3 \cdot 5 = 15\).
- Then calculate \(-6 + 15 = 9\).
2. For the right side, \(\sqrt{16} + 32 \div 8\):
- Calculate \(\sqrt{16} = 4\).
- Then calculate \(32 \div 8 = 4\).
- Now add these results: \(4 + 4 = 8\).
Now we compare the two results:
- The left side evaluates to \(9\).
- The right side evaluates to \(8\).
Now, we need to determine the correct operator to make the statement true:
\(9 \_ \ 8\)
Since \(9 > 8\), we can insert the operator \(>\).
Thus, the correct operator is:
> greater than
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