Consider the following expressions: -6 + 3*5-------sqrt 16 +32 divide 8. Which operator can be inserted to make the statement true?

Answer 1

Let's analyze the given expressions.

1. First Expression: \[ -6 + 3 \times 5 \] We calculate this as follows:

   • First, multiply: \(3 \times 5 = 15\)
   • Then add: \(-6 + 15 = 9\)

2. Second Expression: \[ \sqrt{16} + 32 \div 8 \] We calculate this step by step:

   • First, find the square root: \(\sqrt{16} = 4\)
   • Then divide: \(32 \div 8 = 4\)
   • Finally, add: \(4 + 4 = 8\)

Now, we need to equate the two results we calculated:

• From the first expression, we have: \(9\)
• From the second expression, we have: \(8\)

To make the statement true, we could think about finding an operator to insert between the two expressions.

After computing both expressions, we see \(9\) and \(8\). The difference is \(1\). To make the equation \(9 = 8\) true with an operator, we can insert a subtraction operator:

\[ 9 - 1 = 8 \]

Thus, by inserting a subtraction sign, we can make this statement true:

Final conclusion: The operator that can be inserted is "-" (subtraction).