Question

Consider the following expressions:
$-6+3\cdot 5\quad \sqrt {16}+32\div 8$
Which operator can be inserted to make the statement true?
(1 point)
B.
$\frac {1}{4}$
gt
D

Answer 1

To solve the problem, we need to evaluate the two expressions given and see if we can find an operator (greater than, less than, or equal to) that would make the statement true.

Let's start by calculating each expression:

1. For the first expression:
\[-6 + 3 \cdot 5\]

First, perform the multiplication:
\[3 \cdot 5 = 15\]

Then, add:
\[-6 + 15 = 9\]

So, the value of the first expression is \(9\).

2. For the second expression:
\[\sqrt{16} + 32 \div 8\]

First, calculate the square root:
\[\sqrt{16} = 4\]

Next, perform the division:
\[32 \div 8 = 4\]

Then, add:
\[4 + 4 = 8\]

So, the value of the second expression is \(8\).

Now, we have:
- First expression: \(9\)
- Second expression: \(8\)

Now, we can relate the two results:
We have \(9\) and \(8\), thus:
\[ 9 > 8 \]

Therefore, the appropriate operator that can be inserted between the two expressions is \(>\) (greater than).

The completed statement would thus be:
\[
-6 + 3 \cdot 5 > \sqrt{16} + 32 \div 8
\]
\[
9 > 8
\]

Hence, the answer to the question is that the operator that can be inserted to make the statement true is:
\[
\text{greater than } (>)
\]