Question

calculate the density of a gold ring that has a mass of 15.83 grams and a volume of 0.82 milliliters.

Answer 1

now calculate the density of a gold bar that has a mass of 1,000 grams and a volume of 51.8 milliliters. use the same formula for density

Answer 2

To calculate the density of the gold ring, you can use the formula for density:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

In this case, the mass of the gold ring is 15.83 grams and the volume is 0.82 milliliters. Plugging in these values:

\[
\text{Density} = \frac{15.83 \, \text{grams}}{0.82 \, \text{milliliters}} \approx 19.29 \, \text{grams per milliliter}
\]

Therefore, the density of the gold ring is approximately **19.29 grams per milliliter**.

Answer 3

To calculate the density of the gold bar, we can use the same density formula:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

Given that the mass of the gold bar is 1,000 grams and the volume is 51.8 milliliters, we can substitute these values into the formula:

\[
\text{Density} = \frac{1,000 \, \text{grams}}{51.8 \, \text{milliliters}} \approx 19.31 \, \text{grams per milliliter}
\]

Therefore, the density of the gold bar is approximately **19.31 grams per milliliter**.