Question

What is the period, amplitude and phase shift for:

y=2sin(3x-pi)

Answer 1

In
y = a sin k(x - ß)
the amplitude is a
the period is 2pi/k or 360º/k
there is a phase shift of ß to the right.

Yours:
y=2sin(3x-pi)
= 2sin 3(x - pi/3)

so .....

Answer 2

its pi/3 units to the right :)

Answer 3

Yes, that's correct! The amplitude is 2 and the period is 2pi/3.