Question

state the period, the amplitude and the phase shift of the function y = 1+1/3sin2(x+n/2), hence sketch the curve for the values of x in the range -n/2<x<3n/2. (n is pie couldn't get exact symbol)

Answer 1

I will assume that the 2 after the sin is not an exponent, and that 2(x + pi/2) is the argument of the sine function.

Compare this standard form of the one-dimensional wave equation

A sin (2*pi*x/P -phi)
where A = amplitude
P = period
phi = phase shift.
Ignore the displacement constant, which is the leading "1" in your formula.

Amplitude = 1/3
pi/P = 1 so Period = pi
Phi = phase shift = -pi/2