Asked by Emily
If 20 mL of 0.01 M aqueous HCl is required to neutralize 30 mL of an aqueous solution of NaOH, determine the molarity of the NaOH solution.
==> I got 0.01 M NaOH as my answer. Is this correct?
==> I got 0.01 M NaOH as my answer. Is this correct?
Answers
Answered by
DrBob222
No, it isn't correct although I suspect you worked it correctly. I suspect you simply read your calculator incorrectly.
mL x M = mL x M (you can use this simplified expression since the reaction is 1:1 and ONLY then).
20 x 0.01 = 30 x M
M = (20*0.01)/30 = 0.00667 which rounds to 0.0067 M.
If your calculator is like most, you have it set to read to two places, so the calculator rounds 0.006 to 0.01.
mL x M = mL x M (you can use this simplified expression since the reaction is 1:1 and ONLY then).
20 x 0.01 = 30 x M
M = (20*0.01)/30 = 0.00667 which rounds to 0.0067 M.
If your calculator is like most, you have it set to read to two places, so the calculator rounds 0.006 to 0.01.
Answered by
Emily
Ohhh I see. This makes more sense. Thank you! :)
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