Van't Hoff factor can be associated to the property of the substance (if it's strong electrolyte, weak electrolyte, etc.), and can be approximated by counting the number of ions dissociated in water.
a. i ~ 1 (weak acid, therefore weak electrolyte)
b. i = 2 (strong electrolyte)
c. i = 2 (strong base, therefore strong electrolyte)
d. i = 3 (strong electrolyte)
Therefore, the greatest delta freezing point that you would get is using the van't Hoff factor of Ca(NO3)2.
Hope this helps~ :)
Which of the following aqueous solution of equal molality has the lowest freezing point?
a. H2SO3
b. NaCl
c. NaOH
d. Ca(NO3)2
How do you answer this without looking at their i values from textbooks? I know that
delta(Fpt) = m * K,f * i
and that i is approximately equal to the number of ions dissociated, but in the choices, letters A and D have the same number of ions? Please help.
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