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Question content area top Part 1 Complete the table of values for the following function and then plot the points to graph the...Question
Question content area top
Part 1
Complete the table of values for the following function and then plot the points to graph the function by hand.
f(x)equalsStartFraction 1 Over x minus 2 EndFraction
Question content area bottom
Part 1
x
minus2
minus1
0
1
2
3
4
f(x)equalsStartFraction 1 Over x minus 2 EndFraction
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
(Type integers or simplified fractions. Type N if the function is undefined.)
Part 1
Complete the table of values for the following function and then plot the points to graph the function by hand.
f(x)equalsStartFraction 1 Over x minus 2 EndFraction
Question content area bottom
Part 1
x
minus2
minus1
0
1
2
3
4
f(x)equalsStartFraction 1 Over x minus 2 EndFraction
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
(Type integers or simplified fractions. Type N if the function is undefined.)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To compute the values of the function \( f(x) = \frac{1}{x - 2} \) for the given x-values, we will evaluate the function for each \( x \).
1. **For \( x = -2 \)**:
\( f(-2) = \frac{1}{-2 - 2} = \frac{1}{-4} = -\frac{1}{4} \)
2. **For \( x = -1 \)**:
\( f(-1) = \frac{1}{-1 - 2} = \frac{1}{-3} = -\frac{1}{3} \)
3. **For \( x = 0 \)**:
\( f(0) = \frac{1}{0 - 2} = \frac{1}{-2} = -\frac{1}{2} \)
4. **For \( x = 1 \)**:
\( f(1) = \frac{1}{1 - 2} = \frac{1}{-1} = -1 \)
5. **For \( x = 2 \)**:
\( f(2) = \frac{1}{2 - 2} \) is undefined. So, we will write **N** (not defined).
6. **For \( x = 3 \)**:
\( f(3) = \frac{1}{3 - 2} = \frac{1}{1} = 1 \)
7. **For \( x = 4 \)**:
\( f(4) = \frac{1}{4 - 2} = \frac{1}{2} \)
Now we can summarize the table of values:
| \( x \) | \( f(x) \) |
|---------|-------------------------|
| -2 | -\(\frac{1}{4}\) |
| -1 | -\(\frac{1}{3}\) |
| 0 | -\(\frac{1}{2}\) |
| 1 | -1 |
| 2 | N |
| 3 | 1 |
| 4 | \(\frac{1}{2}\) |
### Summary of Results:
- \( f(-2) = -\frac{1}{4} \)
- \( f(-1) = -\frac{1}{3} \)
- \( f(0) = -\frac{1}{2} \)
- \( f(1) = -1 \)
- \( f(2) = N \) (undefined)
- \( f(3) = 1 \)
- \( f(4) = \frac{1}{2} \)
### Graphing the Points:
On a coordinate system, you can plot the points:
- (-2, -1/4)
- (-1, -1/3)
- (0, -1/2)
- (1, -1)
- (3, 1)
- (4, 1/2)
### Note on the function:
The function has a vertical asymptote at \( x = 2 \), which means that the function approaches infinity or negative infinity as \( x \) approaches 2 from the left or right. Thus, in a graph, there will be a break at that point.
You can sketch the graph based on these points and the characteristics of the function!
1. **For \( x = -2 \)**:
\( f(-2) = \frac{1}{-2 - 2} = \frac{1}{-4} = -\frac{1}{4} \)
2. **For \( x = -1 \)**:
\( f(-1) = \frac{1}{-1 - 2} = \frac{1}{-3} = -\frac{1}{3} \)
3. **For \( x = 0 \)**:
\( f(0) = \frac{1}{0 - 2} = \frac{1}{-2} = -\frac{1}{2} \)
4. **For \( x = 1 \)**:
\( f(1) = \frac{1}{1 - 2} = \frac{1}{-1} = -1 \)
5. **For \( x = 2 \)**:
\( f(2) = \frac{1}{2 - 2} \) is undefined. So, we will write **N** (not defined).
6. **For \( x = 3 \)**:
\( f(3) = \frac{1}{3 - 2} = \frac{1}{1} = 1 \)
7. **For \( x = 4 \)**:
\( f(4) = \frac{1}{4 - 2} = \frac{1}{2} \)
Now we can summarize the table of values:
| \( x \) | \( f(x) \) |
|---------|-------------------------|
| -2 | -\(\frac{1}{4}\) |
| -1 | -\(\frac{1}{3}\) |
| 0 | -\(\frac{1}{2}\) |
| 1 | -1 |
| 2 | N |
| 3 | 1 |
| 4 | \(\frac{1}{2}\) |
### Summary of Results:
- \( f(-2) = -\frac{1}{4} \)
- \( f(-1) = -\frac{1}{3} \)
- \( f(0) = -\frac{1}{2} \)
- \( f(1) = -1 \)
- \( f(2) = N \) (undefined)
- \( f(3) = 1 \)
- \( f(4) = \frac{1}{2} \)
### Graphing the Points:
On a coordinate system, you can plot the points:
- (-2, -1/4)
- (-1, -1/3)
- (0, -1/2)
- (1, -1)
- (3, 1)
- (4, 1/2)
### Note on the function:
The function has a vertical asymptote at \( x = 2 \), which means that the function approaches infinity or negative infinity as \( x \) approaches 2 from the left or right. Thus, in a graph, there will be a break at that point.
You can sketch the graph based on these points and the characteristics of the function!
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