Question

Question content area top
Part 1
Find the quartiles for the set of numbers.
89​, 70​, 63​, 91​, 92​, 96​, 75​, 87​, 71​, 74​, 71
Question content area bottom
Part 1
The minimum is
  
enter your response here.

Answer 1

whats the maximum

Answer 2

whats the second quartile

Answer 3

whats the first quartile

Answer 4

whats the thierd quartile

Answer 5

The minimum is 63.

Answer 6

The maximum is 96.

Answer 7

To find the second quartile, also known as the median, we first need to arrange the numbers in ascending order:

63, 70, 71, 71, 74, 75, 87, 89, 91, 92, 96

There are 11 numbers in total, so the median is the middle value. In this case, the middle value is the 6th number when the numbers are in order:

Median = 75

So, the second quartile or median of the set of numbers is 75.

Answer 8

To find the first quartile, also known as Q1, we need to find the median of the lower half of the data set.
Given the data set arranged in ascending order:
63, 70, 71, 71, 74, 75, 87, 89, 91, 92, 96

We have a total of 11 numbers, which means the lower half has (11+1)/2 = 6 numbers. So, the first quartile is the median of the numbers below the overall median which is 75.

The lower half consists of: 63, 70, 71, 71, 74, 75

Calculating the median of the lower half, we find:
Q1 = (71 + 71)/2
Q1 = 71

Therefore, the first quartile Q1 of the data set is 71.

Answer 9

To find the third quartile, also known as Q3, we need to find the median of the upper half of the data set.
Given the data set arranged in ascending order:
63, 70, 71, 71, 74, 75, 87, 89, 91, 92, 96

We have a total of 11 numbers, which means the upper half has (11)/2 = 5 numbers. So, the third quartile is the median of the numbers above the overall median which is 75.

The upper half consists of: 87, 89, 91, 92, 96

Calculating the median of the upper half, we find:
Q3 = (91 + 92)/2
Q3 = 91.5

Therefore, the third quartile Q3 of the data set is 91.5.