Question
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Part 1
Complete the table of values for the following function and then plot the points to graph the function by hand.
f(x)equalsStartFraction 3 Over x minus 2 EndFraction
Question content area bottom
Part 1
x
minus2
minus1
0
1
2
3
4
f(x)equalsStartFraction 3 Over x minus 2 EndFraction
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
(Type integers or simplified fractions. Type N if the function is undefined.)
Part 1
Complete the table of values for the following function and then plot the points to graph the function by hand.
f(x)equalsStartFraction 3 Over x minus 2 EndFraction
Question content area bottom
Part 1
x
minus2
minus1
0
1
2
3
4
f(x)equalsStartFraction 3 Over x minus 2 EndFraction
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
enter your response here
(Type integers or simplified fractions. Type N if the function is undefined.)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the values of the function \( f(x) = \frac{3}{x - 2} \), we will evaluate this function for each value of \( x \) in the provided table: \( -2, -1, 0, 1, 2, 3, 4 \).
Let's calculate \( f(x) \) for each \( x \):
1. For \( x = -2 \):
\[ f(-2) = \frac{3}{-2 - 2} = \frac{3}{-4} = -\frac{3}{4} \]
2. For \( x = -1 \):
\[ f(-1) = \frac{3}{-1 - 2} = \frac{3}{-3} = -1 \]
3. For \( x = 0 \):
\[ f(0) = \frac{3}{0 - 2} = \frac{3}{-2} = -\frac{3}{2} \]
4. For \( x = 1 \):
\[ f(1) = \frac{3}{1 - 2} = \frac{3}{-1} = -3 \]
5. For \( x = 2 \):
\[ f(2) = \frac{3}{2 - 2} = \frac{3}{0} \rightarrow \text{undefined} \]
6. For \( x = 3 \):
\[ f(3) = \frac{3}{3 - 2} = \frac{3}{1} = 3 \]
7. For \( x = 4 \):
\[ f(4) = \frac{3}{4 - 2} = \frac{3}{2} \]
Now, let's compile these results into the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-2 & -\frac{3}{4} \\
-1 & -1 \\
0 & -\frac{3}{2} \\
1 & -3 \\
2 & \text{N (undefined)} \\
3 & 3 \\
4 & \frac{3}{2} \\
\hline
\end{array}
\]
### Summary of Values:
- \( f(-2) = -\frac{3}{4} \)
- \( f(-1) = -1 \)
- \( f(0) = -\frac{3}{2} \)
- \( f(1) = -3 \)
- \( f(2) = \text{undefined} \)
- \( f(3) = 3 \)
- \( f(4) = \frac{3}{2} \)
### Points to Plot:
- \( (-2, -\frac{3}{4}) \)
- \( (-1, -1) \)
- \( (0, -\frac{3}{2}) \)
- \( (1, -3) \)
- \( (2, \text{undefined}) \)
- \( (3, 3) \)
- \( (4, \frac{3}{2}) \)
To graph the function by hand, plot each of the calculated points and remember that as \( x \) approaches 2, \( f(x) \) approaches \( \pm \infty \), creating a vertical asymptote at \( x = 2 \).
Let's calculate \( f(x) \) for each \( x \):
1. For \( x = -2 \):
\[ f(-2) = \frac{3}{-2 - 2} = \frac{3}{-4} = -\frac{3}{4} \]
2. For \( x = -1 \):
\[ f(-1) = \frac{3}{-1 - 2} = \frac{3}{-3} = -1 \]
3. For \( x = 0 \):
\[ f(0) = \frac{3}{0 - 2} = \frac{3}{-2} = -\frac{3}{2} \]
4. For \( x = 1 \):
\[ f(1) = \frac{3}{1 - 2} = \frac{3}{-1} = -3 \]
5. For \( x = 2 \):
\[ f(2) = \frac{3}{2 - 2} = \frac{3}{0} \rightarrow \text{undefined} \]
6. For \( x = 3 \):
\[ f(3) = \frac{3}{3 - 2} = \frac{3}{1} = 3 \]
7. For \( x = 4 \):
\[ f(4) = \frac{3}{4 - 2} = \frac{3}{2} \]
Now, let's compile these results into the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-2 & -\frac{3}{4} \\
-1 & -1 \\
0 & -\frac{3}{2} \\
1 & -3 \\
2 & \text{N (undefined)} \\
3 & 3 \\
4 & \frac{3}{2} \\
\hline
\end{array}
\]
### Summary of Values:
- \( f(-2) = -\frac{3}{4} \)
- \( f(-1) = -1 \)
- \( f(0) = -\frac{3}{2} \)
- \( f(1) = -3 \)
- \( f(2) = \text{undefined} \)
- \( f(3) = 3 \)
- \( f(4) = \frac{3}{2} \)
### Points to Plot:
- \( (-2, -\frac{3}{4}) \)
- \( (-1, -1) \)
- \( (0, -\frac{3}{2}) \)
- \( (1, -3) \)
- \( (2, \text{undefined}) \)
- \( (3, 3) \)
- \( (4, \frac{3}{2}) \)
To graph the function by hand, plot each of the calculated points and remember that as \( x \) approaches 2, \( f(x) \) approaches \( \pm \infty \), creating a vertical asymptote at \( x = 2 \).
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