Asked by Lyndse

A bag contains 7 red marbles, 2 blue marbles, and 1 green marble. If a marble is selected at random, what is the probability of choosing a marble that is not blue?
7+2+1=10 There are two blue marbles

So is the probability 1/5?
Answered by BubblyStar
Yes
Answered by Lyndse
Thank you!
Answered by Jai
Correct answer is 1-(2/10) => 8/10 => 4/5

in question it mentioned as not blue.
Answered by Anonymous
4/5
Answered by anonymous
4/5 is right
Answered by addisyn
YOU ARE ALL WRONG
Answered by amira
A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?
Answered by value
4+6=10 P(Y)=4/10=2/5 P(G)=6/10=3/5
Answered by Anonymous
7 black marbles and 19 blue marbles
Answered by katr
The probability is 7/5
This event is very likely to happen
This event will not happen.
The probability is 1.
The probability is 0.
this can be the answers
Answered by Anonymous
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