Question
One bag contains 5 red marbles, 4 blue marbles, and 3 yellow marbles, and a second bag contains 4 red marbles, 6 blue marbles, and 5 yellow marbles. If Lydia randomly draws one marble from each bag, what is the probability that they are both not yellow?
Answers
MathMate
The two draws are independent.
So the probability of getting a yellow in both bags is the product of the probability of getting a yellow in each bag.
P1(Y)=3/12
P2(Y)=5/15
So
P(Y,Y)=P1(Y)*P2(Y)
So the probability of getting a yellow in both bags is the product of the probability of getting a yellow in each bag.
P1(Y)=3/12
P2(Y)=5/15
So
P(Y,Y)=P1(Y)*P2(Y)
Anonymous
ryrrr7o
Anonymous
1/12
Andrew
The question asks the opposite... not yellow.
so 9/12 * 10/15 = .75 * .666 = 50%
so 9/12 * 10/15 = .75 * .666 = 50%
Marty Murray
Andrew has it right.