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What is the LCD in its factored form of the following rational expression subtraction? x2+2xx2+7x−8−xx−1 (1 point) Responses (x...Asked by bob
                What is the LCD in its factored form of the following rational expression subtraction?
x2+2xx2+7x−8−xx−1
(1 point)
Responses
x(x+2)
x left parenthesis x plus 2 right parenthesis
(x−1)2(x+8)
left parenthesis x minus 1 right parenthesis squared left parenthesis x plus 8 right parenthesis
(x−1)(x+8)
left parenthesis x minus 1 right parenthesis left parenthesis x plus 8 right parenthesis
(x−1)(x2+7x−8)
            
        x2+2xx2+7x−8−xx−1
(1 point)
Responses
x(x+2)
x left parenthesis x plus 2 right parenthesis
(x−1)2(x+8)
left parenthesis x minus 1 right parenthesis squared left parenthesis x plus 8 right parenthesis
(x−1)(x+8)
left parenthesis x minus 1 right parenthesis left parenthesis x plus 8 right parenthesis
(x−1)(x2+7x−8)
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find the least common denominator (LCD) in its factored form of the given rational expression subtraction:
\[
\frac{x^2 + 2x}{x^2 + 7x - 8} - \frac{x}{x - 1}
\]
we will first factor each denominator.
1. **Factor the first denominator** \(x^2 + 7x - 8\):
We need to find two numbers that multiply to \(-8\) and add to \(7\). These numbers are \(8\) and \(-1\). Therefore:
\[
x^2 + 7x - 8 = (x + 8)(x - 1)
\]
2. **Factor the second denominator** \(x - 1\):
This is already factored.
Now that we have the denominators factored, the denominators are:
- The first denominator: \((x + 8)(x - 1)\)
- The second denominator: \((x - 1)\)
To determine the least common denominator (LCD), we take the highest power of each factor present in the denominators:
- From \((x + 8)\), we take \(x + 8\).
- From \((x - 1)\), we take \((x - 1)\) (since it appears in both).
Thus, the LCD is:
\[
\text{LCD} = (x + 8)(x - 1)
\]
Therefore, the correct response, expressed in its factored form, is:
\[
(x - 1)(x + 8)
\]
So the answer is:
**(x−1)(x+8)**.
    
\[
\frac{x^2 + 2x}{x^2 + 7x - 8} - \frac{x}{x - 1}
\]
we will first factor each denominator.
1. **Factor the first denominator** \(x^2 + 7x - 8\):
We need to find two numbers that multiply to \(-8\) and add to \(7\). These numbers are \(8\) and \(-1\). Therefore:
\[
x^2 + 7x - 8 = (x + 8)(x - 1)
\]
2. **Factor the second denominator** \(x - 1\):
This is already factored.
Now that we have the denominators factored, the denominators are:
- The first denominator: \((x + 8)(x - 1)\)
- The second denominator: \((x - 1)\)
To determine the least common denominator (LCD), we take the highest power of each factor present in the denominators:
- From \((x + 8)\), we take \(x + 8\).
- From \((x - 1)\), we take \((x - 1)\) (since it appears in both).
Thus, the LCD is:
\[
\text{LCD} = (x + 8)(x - 1)
\]
Therefore, the correct response, expressed in its factored form, is:
\[
(x - 1)(x + 8)
\]
So the answer is:
**(x−1)(x+8)**.
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