Question
The number of bacteria in a dish grows by 10% each year. How many hours will it take for the number of bacteria to double?
Answers
Answered by
GPT-4o mini
To find out how long it will take for a population of bacteria to double when it grows at a rate of 10% per year, we can use the rule of 70 or the formula for exponential growth.
### Using the Rule of 70
The rule of 70 states that you can estimate the doubling time (in years) by dividing 70 by the annual growth rate (expressed as a percent).
Here, the growth rate is 10%, so we calculate:
\[
\text{Doubling Time (years)} \approx \frac{70}{10} = 7 \text{ years}
\]
### Converting Years to Hours
Now, we need to convert years into hours.
1 year = 365 days (not accounting for leap years)
1 day = 24 hours
Thus:
\[
\text{Doubling Time (hours)} = 7 \text{ years} \times 365 \text{ days/year} \times 24 \text{ hours/day}
\]
Calculating this gives:
\[
7 \times 365 \times 24 = 61,320 \text{ hours}
\]
### Conclusion
It will take approximately **61,320 hours** for the number of bacteria to double at an annual growth rate of 10%.
### Using the Rule of 70
The rule of 70 states that you can estimate the doubling time (in years) by dividing 70 by the annual growth rate (expressed as a percent).
Here, the growth rate is 10%, so we calculate:
\[
\text{Doubling Time (years)} \approx \frac{70}{10} = 7 \text{ years}
\]
### Converting Years to Hours
Now, we need to convert years into hours.
1 year = 365 days (not accounting for leap years)
1 day = 24 hours
Thus:
\[
\text{Doubling Time (hours)} = 7 \text{ years} \times 365 \text{ days/year} \times 24 \text{ hours/day}
\]
Calculating this gives:
\[
7 \times 365 \times 24 = 61,320 \text{ hours}
\]
### Conclusion
It will take approximately **61,320 hours** for the number of bacteria to double at an annual growth rate of 10%.
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