Asked by hudson
The number of bacteria in a culture after x days is represented by the function f(x)=x4−3x2
. What function represents the average number of bacteria in the culture after x days?
Enter the missing values.
(1 point)
(fg)(x)=
$$
. What function represents the average number of bacteria in the culture after x days?
Enter the missing values.
(1 point)
(fg)(x)=
$$
Answers
Answered by
GPT-4o mini
To find the function that represents the average number of bacteria in the culture after \( x \) days, we need to divide the total number of bacteria \( f(x) \) over the time period. The average number of bacteria over the interval from day 0 to day \( x \) can be represented as follows:
\[
\text{Average Number of Bacteria} = \frac{1}{x} \int_0^x f(t) \, dt
\]
where \( f(t) = t^4 - 3t^2 \).
So, we first need to compute the integral \( \int_0^x (t^4 - 3t^2) \, dt \):
1. Compute the integral:
\[
\int (t^4 - 3t^2) \, dt = \frac{t^5}{5} - t^3 + C
\]
2. Now evaluate the definite integral from 0 to \( x \):
\[
\int_0^x (t^4 - 3t^2) \, dt = \left[ \frac{t^5}{5} - t^3 \right]_0^x = \left( \frac{x^5}{5} - x^3 \right) - \left( 0 - 0 \right) = \frac{x^5}{5} - x^3
\]
3. Now plug this into the average formula:
\[
\text{Average Number of Bacteria} = \frac{1}{x} \left( \frac{x^5}{5} - x^3 \right) = \frac{x^5}{5x} - \frac{x^3}{x} = \frac{x^4}{5} - x^2
\]
Therefore, the average number of bacteria after \( x \) days is represented by the function:
\[
A(x) = \frac{x^4}{5} - x^2
\]
Thus, the final answer for \( (fg)(x) \) which typically denotes the average in this context is:
\[
(fg)(x) = \frac{x^4}{5} - x^2
\]
\[
\text{Average Number of Bacteria} = \frac{1}{x} \int_0^x f(t) \, dt
\]
where \( f(t) = t^4 - 3t^2 \).
So, we first need to compute the integral \( \int_0^x (t^4 - 3t^2) \, dt \):
1. Compute the integral:
\[
\int (t^4 - 3t^2) \, dt = \frac{t^5}{5} - t^3 + C
\]
2. Now evaluate the definite integral from 0 to \( x \):
\[
\int_0^x (t^4 - 3t^2) \, dt = \left[ \frac{t^5}{5} - t^3 \right]_0^x = \left( \frac{x^5}{5} - x^3 \right) - \left( 0 - 0 \right) = \frac{x^5}{5} - x^3
\]
3. Now plug this into the average formula:
\[
\text{Average Number of Bacteria} = \frac{1}{x} \left( \frac{x^5}{5} - x^3 \right) = \frac{x^5}{5x} - \frac{x^3}{x} = \frac{x^4}{5} - x^2
\]
Therefore, the average number of bacteria after \( x \) days is represented by the function:
\[
A(x) = \frac{x^4}{5} - x^2
\]
Thus, the final answer for \( (fg)(x) \) which typically denotes the average in this context is:
\[
(fg)(x) = \frac{x^4}{5} - x^2
\]
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