Question

Evaluate the definite integral.
xe^(–x^2)dx from 0 to 6

Answer 1

dx x e^-x^2

well d/dx (e^-x^2) = -2 x e^-x^2

so I will guess

(-1/2) e^-x^2 from 0 to 6

(-1/2) e^-36 - (-1/2)e^0

looks like about 1/2