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Evaluate the definite integral.
S4 (-3x+4) dx
1
S4 (-3x+4) dx
1
Answers
Answered by
Damon
integral from 1 to 4 of (-3x+4) dx ?
that is the sum of two integrals
-3 x dx and 4 dx
the first one is - (3/2) x^2 at 4 - at 1
= -(3/2)(16 - 1)
= -(3/2) 15 = -45/2
the second one is 4 (4-1) = 12
so I get
-45/2 + 24/2 = -21/2
that is the sum of two integrals
-3 x dx and 4 dx
the first one is - (3/2) x^2 at 4 - at 1
= -(3/2)(16 - 1)
= -(3/2) 15 = -45/2
the second one is 4 (4-1) = 12
so I get
-45/2 + 24/2 = -21/2
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