Asked by anonymous

How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?
Answered by drwls
8 (teams) x 7 (possible opponents of each team) / 2 = 28

The division by two is necessary to avoid counting each game twice.
Answered by drwls
I should have multiplied by 2 since each pair of teams plays twice. That makes the final number 56
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