Asked by m
How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?
I figured 8x7x2=112 since this is 8 teams and 7 opponents per team and playing twice am i right?
I figured 8x7x2=112 since this is 8 teams and 7 opponents per team and playing twice am i right?
Answers
Answered by
bobpursley
lets try it manually with four teams, ABCS
AB
AD
AC
BD
BC
CD
So your method doesnt work for four teams.
NOW consider if it were 4*3/2=6 That works. So is the answer now 8*7/2
Hint: one divides by two because AB is the same as BA.
AB
AD
AC
BD
BC
CD
So your method doesnt work for four teams.
NOW consider if it were 4*3/2=6 That works. So is the answer now 8*7/2
Hint: one divides by two because AB is the same as BA.
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