Asked by Priscilla

An electrostastic force of 20.0 newtons is exerted on a charge of 8.00 x 10^/2 C at point P in an electric field. The magnitude of the electric field strength at P is

Given:
Fe = 20 B
q = 8.00 x 10^/2 C
Answered by drwls
Use F = Q * E

Solve for E, in Newtons per Coulomb

Fe = 50 N(ewtons), NOT 50 B
I think you made a typing error

I do not understand why you put an / in front of the exponent, 2, of the charge (Q)
Answered by Priscilla
Oh im really sorry, its 8.00 x 10^-2
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