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Two 6.0 μF capacitors, two 2.2 kΩ resistors, and a 14.5 V source are connected in series. Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.40 mA
15 years ago

Answers

bobpursley
RC= 4.4*3.0E-6

I=14.5/4.4 * e^t/RC

take the log (e) of each side.

ln 1.40=ln 14.5 - ln4.4 + t/RC
solve for t.
15 years ago

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