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Two capacitors C1 = 7.00 µF and C2 = 11.0 µF are connected in series to a 9.00 V battery.
(a) Find the equivalent capacitance of the combination.
µF
(b) Find the potential difference across each capacitor.
(c) Find the charge on each capacitor.
(a) Find the equivalent capacitance of the combination.
µF
(b) Find the potential difference across each capacitor.
(c) Find the charge on each capacitor.
Answers
Answered by
Henry
a. Ct = C1*C2?(C1+C2)
Ct = 7*11/(7+11) = 4.28 uF. = Total capacitance.
b. Qt = Ct*V = 4.28 * 9 = 38.5 uC=Q1=Q2
Q1 = C1*V1 = 38.5
7 * V1 = 38.5
V1 = 5.5 Volts.
C2 * V2 = Qt
V2 = 38.5/11 = 3.5 Volts.
c. Q1 = Q2 = Qt = 38.5 uC.
Ct = 7*11/(7+11) = 4.28 uF. = Total capacitance.
b. Qt = Ct*V = 4.28 * 9 = 38.5 uC=Q1=Q2
Q1 = C1*V1 = 38.5
7 * V1 = 38.5
V1 = 5.5 Volts.
C2 * V2 = Qt
V2 = 38.5/11 = 3.5 Volts.
c. Q1 = Q2 = Qt = 38.5 uC.
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