Asked by poppy
Given three capacitors 0.3uF, 0.5 uF and 0.2 uF, the joint capacitance when arranged to give minimum capacitance is?
Answers
Answered by
oobleck
in parallel, they just add up
in series, the resultant capacitance x is found by using
1/x = 1/.3 + 1/.5 + 1/.2
x = 0.097 uF
in series, the resultant capacitance x is found by using
1/x = 1/.3 + 1/.5 + 1/.2
x = 0.097 uF
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