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Cones, Cylinders, & Spheres Unit Test 2 of 152 of 15 Items Question Use the image to answer the question. An oblique cylinder i...Asked by AI Help
Cones, Cylinders, & Spheres Unit Test
2 of 152 of 15 Items
Question
Use the image to answer the question.
An oblique cylinder is labeled with a height of 15 centimeters and radius 5 centimeters.
Find the surface area of the cylinder below. Use the approximation 3.14 for pi.
(1 point)
Responses
1,099 square centimeters
1,099 square centimeters
628 centimeters
628 centimeters
628 square centimeters
628 square centimeters
533.8 square centimeters
Answers
Answered by
AI Help
are you sure?
Answered by
GPT-4o
To find the surface area of an oblique cylinder, we still use the same formulas as a right cylinder since the surface area depends on the radius and height, which are the same. The surface area \( \text{SA} \) of a cylinder is given by the formula:
\[ \text{SA} = 2\pi r(h + r) \]
Where:
- \( r \) is the radius
- \( h \) is the height
- \( \pi \approx 3.14 \)
Given:
- \( r = 5 \) cm
- \( h = 15 \) cm
- \( \pi \approx 3.14 \)
Plugging these values into the formula:
\[ \text{SA} = 2 \times 3.14 \times 5 \times (15 + 5) \]
\[ \text{SA} = 2 \times 3.14 \times 5 \times 20 \]
\[ \text{SA} = 2 \times 3.14 \times 100 \]
\[ \text{SA} = 6.28 \times 100 \]
\[ \text{SA} = 628 \text{ square centimeters} \]
So, the surface area of the oblique cylinder is:
\[ \boxed{628 \text{ square centimeters}} \]
\[ \text{SA} = 2\pi r(h + r) \]
Where:
- \( r \) is the radius
- \( h \) is the height
- \( \pi \approx 3.14 \)
Given:
- \( r = 5 \) cm
- \( h = 15 \) cm
- \( \pi \approx 3.14 \)
Plugging these values into the formula:
\[ \text{SA} = 2 \times 3.14 \times 5 \times (15 + 5) \]
\[ \text{SA} = 2 \times 3.14 \times 5 \times 20 \]
\[ \text{SA} = 2 \times 3.14 \times 100 \]
\[ \text{SA} = 6.28 \times 100 \]
\[ \text{SA} = 628 \text{ square centimeters} \]
So, the surface area of the oblique cylinder is:
\[ \boxed{628 \text{ square centimeters}} \]
Answered by
GPT-4o
Yes, I am confident in the calculation, but let's go through it once more to ensure everything checks out.
The surface area formula for a cylinder is:
\[ \text{SA} = 2\pi r(h + r) \]
Given:
- \( r = 5 \) cm
- \( h = 15 \) cm
- \( \pi \approx 3.14 \)
We'll substitute the values into the formula:
\[ \text{SA} = 2 \times 3.14 \times 5 \times (15 + 5) \]
\[ \text{SA} = 2 \times 3.14 \times 5 \times 20 \]
\[ \text{SA} = 2 \times 3.14 \times 100 \]
\[ \text{SA} = 6.28 \times 100 \]
\[ \text{SA} = 628 \text{ square centimeters} \]
This confirms that the surface area of the oblique cylinder is indeed \( 628 \text{ square centimeters} \). The answer remains:
\[ \boxed{628 \text{ square centimeters}} \]
The surface area formula for a cylinder is:
\[ \text{SA} = 2\pi r(h + r) \]
Given:
- \( r = 5 \) cm
- \( h = 15 \) cm
- \( \pi \approx 3.14 \)
We'll substitute the values into the formula:
\[ \text{SA} = 2 \times 3.14 \times 5 \times (15 + 5) \]
\[ \text{SA} = 2 \times 3.14 \times 5 \times 20 \]
\[ \text{SA} = 2 \times 3.14 \times 100 \]
\[ \text{SA} = 6.28 \times 100 \]
\[ \text{SA} = 628 \text{ square centimeters} \]
This confirms that the surface area of the oblique cylinder is indeed \( 628 \text{ square centimeters} \). The answer remains:
\[ \boxed{628 \text{ square centimeters}} \]
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