Question
Cones, Cylinders, & Spheres Unit Test 5 of 155 of 15 Items Question Use the image to answer the question. Find the volume of the cylinder, in cubic millimeters. Round your answer to the nearest hundredth. (1 point)
Answers
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder, and
- \( h \) is the height of the cylinder.
Since you mentioned an image needed to answer the question but did not provide any specific measurements for the radius or height, I can't compute the volume directly without that information.
If you can give me the values for the radius and height of the cylinder, I can help you calculate the volume and round it to the nearest hundredth.
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder, and
- \( h \) is the height of the cylinder.
Since you mentioned an image needed to answer the question but did not provide any specific measurements for the radius or height, I can't compute the volume directly without that information.
If you can give me the values for the radius and height of the cylinder, I can help you calculate the volume and round it to the nearest hundredth.
r= 8
h=13
h=13
GPT-4o mini
Given the radius \( r = 8 \) mm and height \( h = 13 \) mm, you can calculate the volume of the cylinder using the formula:
\[
V = \pi r^2 h
\]
Substituting the given values:
\[
V = \pi (8^2) (13)
\]
Calculating \( 8^2 \):
\[
8^2 = 64
\]
Now substituting back:
\[
V = \pi (64)(13)
\]
Calculating \( 64 \times 13 \):
\[
64 \times 13 = 832
\]
Now substituting in the volume formula:
\[
V = \pi (832)
\]
Now, using the approximation \( \pi \approx 3.14159 \):
\[
V \approx 3.14159 \times 832
\]
Calculating this gives:
\[
V \approx 2617.76 \text{ cubic millimeters}
\]
Rounding to the nearest hundredth:
\[
V \approx 2617.76 \text{ mm}^3
\]
Therefore, the volume of the cylinder is approximately **2617.76 cubic millimeters**.
\[
V = \pi r^2 h
\]
Substituting the given values:
\[
V = \pi (8^2) (13)
\]
Calculating \( 8^2 \):
\[
8^2 = 64
\]
Now substituting back:
\[
V = \pi (64)(13)
\]
Calculating \( 64 \times 13 \):
\[
64 \times 13 = 832
\]
Now substituting in the volume formula:
\[
V = \pi (832)
\]
Now, using the approximation \( \pi \approx 3.14159 \):
\[
V \approx 3.14159 \times 832
\]
Calculating this gives:
\[
V \approx 2617.76 \text{ cubic millimeters}
\]
Rounding to the nearest hundredth:
\[
V \approx 2617.76 \text{ mm}^3
\]
Therefore, the volume of the cylinder is approximately **2617.76 cubic millimeters**.
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