A driving pulley rotates at 3r/s and has a diameter of 300cm. The pulley exerts a force of 2kN at a point on its periphery

Answer 1

To find the torque exerted by the pulley, we first need to determine the angular velocity of the pulley in radians per second.

Given:
Angular velocity, ω = 3 rad/s
Diameter, D = 300 cm

Radius, r = D/2 = 150 cm = 1.5 m

Now, we can calculate the torque (τ) exerted by the pulley using the formula: τ = Fr

Given force, F = 2 kN = 2000 N

τ = 2000 N * 1.5 m = 3000 Nm

Therefore, the torque exerted by the pulley is 3000 Nm.