Question
During 0.21 s, a wheel rotates through an angle of 2.10 rad as a point on the periphery of the wheel moves with a constant speed of 2.12 m/s. What is the radius of the wheel?
Answers
Henry
d = 2.12m/s * 0.21s = 0.4452 m.
C=(6.28rad/2.10rad) * 0.4452 m=1.33 m. =
Circumference.
C =3.14 * 2r = 1.33 m.
6.28r = 1.33
r = 0.212 m. = Radius of the wheel.
C=(6.28rad/2.10rad) * 0.4452 m=1.33 m. =
Circumference.
C =3.14 * 2r = 1.33 m.
6.28r = 1.33
r = 0.212 m. = Radius of the wheel.